[mariolima]

Hi:

I need a very simple script, in CGI-Perl or even bash language, and to be started from a browser form, to just read a file, finding a specific line by comparing to a received pattern, and from this line ahead always list 3 lines.

Considering, for instance, this file, that I would call: rejected.log:

11111111 22222222 33333333
22222222 bbbbbbbb ccccccccc
jdjfheduf sdkfheuf idifhdihfif
difheihfi eiofjeif efi9ef eijh eifje fef
aaaaaaaa 22222222 33333333
ddddddddd bbbbbbbb ccccccccc
kdjgirir iofejgiejrg ioerugejge
ljeri 98rg398 gio3jrg9 3rjoer

If I run the script by:

scriptname aaaaaaaa

It should list the lines:

aaaaaaaa 22222222 33333333
ddddddddd bbbbbbbb ccccccccc
kdjgirir iofejgiejrg ioerugejge

Please, note that it also should list all the existing occurrences of the same aaaaaaaa through the file.

I thank a lot in advance for this so special help.

Mario./

[codejockey]

Would something like this do what you want?

#! /bin/sh

FILENAME=rejected.log
PATTERN="$1"

if [ -z "$PATTERN" ]
then
    echo must supply a search parameter ... exiting ...
    exit 1
else
    egrep -A 2 "$PATTERN" $FILENAME
fi

Of course, you could also supply the filename to be searched as an argument to the script.