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Need help with a equation


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Mosaic1's Avatar
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Join Date: Aug 2001
20-Dec-2004, 09:39 PM #16
EDIT When I said
Finally Convert the minutes to decimal form.
Decimal Hours = Hours + (Minutes * 1.6666667)


I should have said Finally Convert the minutes to decimal form and add them to the hours.
Mosaic1's Avatar
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Join Date: Aug 2001
21-Dec-2004, 01:53 AM #17
For one entire day:
Difference = ((1130 - 800) + (1700 - 1200)) / 100
Hours = Difference Mod 100
Minutes = (Difference - Hours)
DecHours = Hours + (Minutes * 1.6666667)
Final result (DecHours) = 8.5 hours.

EDIT> No. It didn't take me that long to figure it out. I just came by to see if you had answered.


Here's one for you. It's about 10 degrees here. How many lumps of coal will Santa have to leave to keep this house warm?

Last edited by Mosaic1 : 21-Dec-2004 02:06 AM.
haplo210's Avatar
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Location: Near where Irn Bru's made
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21-Dec-2004, 12:26 PM #18
answer not as many as we need here, minus 3.
Mosaic1's Avatar
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21-Dec-2004, 01:01 PM #19
LOL Ouch. Now that's cold.

Merry Christmas.
haplo210's Avatar
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Join Date: Nov 2004
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21-Dec-2004, 02:02 PM #20
its like a message...welcome to scotland...not only does your car freeze on the outside, but also the inside of the windscreen lol.

Merry Christmas.
Couriant's Avatar
Computer Specs
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21-Dec-2004, 02:28 PM #21
LOL @ you guys

I have taken what you have done for me so thank you. I will let you know what I get in my project on Thursday!

BTW that's -3oC = 15-20oF
Mosaic1's Avatar
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Join Date: Aug 2001
21-Dec-2004, 09:23 PM #22
haplo210,
LOL welcome to scotland... That's hilarious. Good luck keeping warm.



Tidus4Yuna,

Good luck. Oh no! Fatal Flaw in logic. It only works on alternate Tuesdays between 2 and 4 pm. I'll be interested to see how you do.


Mo
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