[Villanz]

Could someone please tell me what is wrong with this statement?

person.name = "Dan";

...where 'person' is the name of the structure and 'name' is the name of a string variable within it.
The compiler says something about incompatible types in assignment.

[AGCurry]

It depends on whether name is an array of characters or a pointer to char.

If name is declared as char *name, then your assignment is okay.

If it's declared as char name[20], it's not.

[Villanz]

Thanks for the reply.
It's declared as char name[20]. Is there a way i can make it work like that or will i have to use a pointer?

[coderitr]

strcpy( person.name, "Dan" );

[IMM]

I'm not recommending it in this case - but if I want to have a char pointer to a fixed size buffer at compile time in C - I'll usu. do the following as the declaration - giving me both methods so that I can address it with the char* or as the array

#define BUFFER_SIZE 20 
  char name_buf[BUFFER_SIZE], *name_ptr = name_buf;

This is an easy one to make serious mistakes with tho'

[AGCurry]

Originally Posted by Villanz

Thanks for the reply.
It's declared as char name[20]. Is there a way i can make it work like that or will i have to use a pointer?

struct whatever
{
char *name ;
char *phone ;
} ;

.
.
.
struct whatever person ;

person.name = "Dan" ;