[redivivus]

#include <cstdio>
#include <iostream>

int main()
{
	char a = '\0', b = '!', c = 'd', d = 'l', e = 'r', f = 'o',
		g = 'w', h = ' ', i = ',', j = 'o', k = 'l', l = 'l', 
		m = 'e', n = 'H';

	puts(& n);
    system("PAUSE");

}

Output:

Hello, world!
Press any key to continue...


No comprendo... Looks like the string "Hello, world" is stored backwards in a char array.

[AGCurry]

Pretty weird.

But it's not an array - it's just a list of initialized char variables; if it were an array, the program probably would have had a memory fault, as you'd expect.

I think it illustrates nothing more than the way that storage for scalar variables is allocated; last in, first out, as in a stack. It is NOT safe programming, because we as programmers shouldn't make such assumptions about memory allocations.

[Shadow2531]

Originally Posted by AGCurry

It is NOT safe programming, because we as programmers shouldn't make such assumptions about memory allocations.

Exactly. For example, the output will break if you compile with optimizations.

[blaqDeaph]

This only works because it assumes that the variables are assigned sequentially in the memory (stack operations assign the memory locations backwords). It won't work if for some reason, the data locations wasn't assigned sequentially.

Not to mention it's less efficient cuz the compiler/program will have to keep tabs on more variables (thus more overhead)