[bootsiebella]

Can anyone help me write these algorithm in C++

Write an algorithm to read a sequence of integers, ignoring all numbers that are less than 1. Count how many even and odd numbers there are, and print these counts. For example, with input 7 25 100 2 -6 1 0 3, the output should be
Even = 2, odd = 4
There were two even numbers (100 and 2), four odd numbers (7, 25, 1, and 3), and two numbers were ignored (-6 and 0). Your algorithm should work for any input, not just this example.

4. A tollbooth needs a program that tells how much to charge drivers. The charge is based on how many people are in the vehicle. To encourage car-pooling, the cost is lower for more people. The cost is $6.00 for one person, 1/2 of that ($3.00) for two people, 1/3 ($2.00) for three people, and in general 6/n for n people.

Write an algorithm that reads the number of people in the vehicle and prints the cost. Print "ERROR" if a number less than 1 is entered. It continues reading input in a loop.

[Shadow2531]

For the first one, how far have you gotten? Have you figured out how to check if an integer is odd or not?

Are you allowed to use std:string, std::vector and std::istringstream?

[TheRobatron]

For the first one you'll need a function to check if the number is even:

bool even(int num) {
if (num % 2 == 0) {
return true;
} else {
return false;
}
}

Then you can keep totals of each:

int totalEvens, totalOdds;
if (even(num)) {
totalEvens++;
} else {
totalOdds++;
}

You can put it all in a for or while loop and to check if the number is valid all you need is a simple if statement to check if the input is more than 0.