[PEP]

Starts off easy

D/Dx X = ???

Solve then post your own!!! WHOOOO

[Bichey]

ans: 1

show that d/dx(x^n)=nx^(n-1) where n is a +ve integer.

you may use product rule

here ^ represents "to the power"

[PEP]

well.... power rule..... i dont see how the product rule would be used to prove it... you can just take x^2 and use the limit as delta x -> 0 to prove it. once done youd get 2x^(2-1) = 2x.
With product rule, i guess you can do something like d/dx (x^2)(1) = 2x(1) + x^2(0) = 2x... so that could be an example of product rule.


SOLVE
d/dx tanx

[Bichey]

d/dx tan x =sec^2 x

by product rule, u can solve my above prob easily as follows

let f(x)=x^n=x.x.x.x.x.......x (n factors)
Therefore, f'(x)=x.x.x...(n-1) factors + x.x.x....(n-1) factors + .... to n terms = nx^(n-1)

Q: d/dx (root x) = ?

[PEP]

lol... thats a confusing explanation....

d/dx root x = 1/2rootx


Q: d/dx ln(sinx + 3)

[PEP]

Interesting!!! i would have thought more people knew calculus around here!?!?

[oil painter]

Originally Posted by PEP

Interesting!!! i would have thought more people knew calculus around here!?!?

Maybe they just don't want to play your game!!!

[PEP]

Why not its fun!!!

[numnum]

ugh, you just reminded me that i need to study calculus =\

[Bichey]

Originally Posted by numnum

ugh, you just reminded me that i need to study calculus =\

he he

[PEP]

Is d/dx ln(sinx + 3) really that hard?!?!?

[KMW]

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeek! calculus
never touch it myself


had me hit and run, ya won't see me in here again, to tough on my mental health

[PEP]

lol calculus isnt even that hard.... it really isnt... now discrete mathematics on the other hand is morbidly mind numbing...

[PEP]

goshdarn it!!!!

doesnt anybody know what a derivative even is?!?!?!

[PEP]

lol my answer in post 5 was accidently wrong... d/dx of root x is 1/(2rootx)