[knight_47]

well the codes at least compiling, but theres a small problem. The only way I can think of to fix is by using form action="phpfile.php" but I'm wondering why this doesn't work.

The link. it's not suppose to show the result unless you hit enter. How can I prevent this?

the code:

PHP Code:

<?php 

$a1 = ($_POST['a1'] == "a1");
$a2 = ($_POST['b1'] == "b2");
$a3 = ($_POST['c1'] == "c2");
$a4 = ($_POST['d1'] == "d2");
$a5 = ($_POST['e1'] == "e1");  

if ($_POST['Submit'] AND $a1 AND $a2 AND $a3 AND $a4 AND $a5) 
{
echo "Results: <br />";
echo "Congratulations! You got all the answers right! That is a 100%!";
}
else
{
echo "Opps! <br />";
echo "One or more problems are incorrect, please go back and re-check your answers!";
}

?>

[brendandonhu]

What exactly are you trying to do with this?
$a1 = ($_POST['a1'] == "a1");
$a2 = ($_POST['b1'] == "b2");
$a3 = ($_POST['c1'] == "c2");
$a4 = ($_POST['d1'] == "d2");
$a5 = ($_POST['e1'] == "e1");

[knight_47]

lol i know it's stupid, but I'm just trying to prefect my variable making. :P

[covert215]

Test for NULL. If NULL, echo nothing. Nest the if statements.

[brendandonhu]

No need to nest the if() that will just make it longer. Just use this for your variables.
$a1 = $_POST['a1'];
$a2 = $_POST['b1'];
$a3 = $_POST['c1'];
$a4 = $_POST['d1'];
$a5 = $_POST['e1'];

[knight_47]

What do you mean next the if()?

I fixed the variables, thanks.

[namenotfound]

Originally Posted by knight_47

What do you mean next the if()?

I fixed the variables, thanks.

nesting would be like this

if (this == that) {
if (here == there) {
echo "something";
}
}

One IF statement nested within another.

[knight_47]

Originally Posted by namenotfound

nesting would be like this

if (this == that) {
if (here == there) {
echo "something";
}
}

One IF statement nested within another.

But wouldn't that be the same as

if xxxx && xxxxx && xxxxx
{
echo "x";
}

[namenotfound]

I guess so. I was just giving an example of what "nesting" is

[covert215]

Originally Posted by knight_47

But wouldn't that be the same as

if xxxx && xxxxx && xxxxx
{
echo "x";
}

That is NOT the same, when you use IF-ELSE statements. It alters the flow of logic.

[knight_47]

So how would I fix the problem?

I'm pretty much a beginner at PHP, and don't know much as of now, so I get easily confused...

[brendandonhu]

Your code doesn't really make sense because you aren't checking the answers to the quiz anywhere but here's a start

PHP Code:

<?php
$a1 = $_POST['a1'];
$a2 = $_POST['b1'];
$a3 = $_POST['c1'];
$a4 = $_POST['d1'];
$a5 = $_POST['e1'];

if(isset($_POST['submit']))
{
  if ($a1 AND $a2 AND $a3 AND $a4 AND $a5)
  {
    echo "Results: <br />";
    echo "Congratulations! You got all the answers right! That is a 100%!";
  }
  else
  {
    echo "Opps! <br />";
    echo "One or more problems are incorrect, please go back and re-check your answers!";
  }
}
?>

[knight_47]

What do you mean the code doesn't make sense?

If the user hits submit, AND this, AND that, AND this, then echo, Congrats!

If not, echo, something else.

I haven't tried you're code yet, i'm not home yet, but I will in a bit.

[brendandonhu]

I mean your code is going to tell them they got 100% regardless of what answers they select.

[namenotfound]

Knight, why don't you just use the method I posted on the other site?

http://xenweb.net/forums/16333-post10.html

It works, and you wouldn't be pulling your hair out right now trying to get that code to work
If you want I can write it up using your questions and answers