another physics q...

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I was in a head-on collision last October. 55 mph - 0 mph in 7 feet. How many G's is that?

V initial
V final
T time
D distance
G 32ft/(sec x sec)

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V^2 - Vo^2 = 2*a*d

55 MPH = 80.6666667 feet per second
0^2 - 80.67^2 = 2*a*7

Your acceleration was -464.79 feet per second^2

Divide that by G, 32, and you get -14.5 G's.

That's a lotta force.
 

TRS-80 vet

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McTimson said:
V^2 - Vo^2 = 2*a*d

55 MPH = 80.6666667 feet per second
0^2 - 80.67^2 = 2*a*7

Your acceleration was -464.79 feet per second^2

Divide that by G, 32, and you get -14.5 G's.

That's a lotta force.
Yeah, it sure was (that I can remember).:eek:
 

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