Application opening speed right after Windows startup

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karbo

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Whenever you boot your system, applications openned for the first time take more time to open but after they've been openned at least one time, the process speeds up. Can you tell me if there's a way for Windows to not initialize this speed everytime the computer is rebooted, so that it can stay always at maximum speed? It might have something to do with cache or something.

Thank you
 
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If the time difference is more than a few seconds then you need to perform maintenance on your PC. Clean up the temp folders, delete all the junk, remove old applications, upgrade all your software and OS, defrag your hard disk, etc.

If you have a clean and current system, you really shouldn't notice these things. However a 3 year old or more system will notice these things moreso than it did when it was brand new.

Unless you pre-load that caches (I do not know of any tool offhand that does this) it wouldn't make any difference, but you'd cause other issues so doing I'd think.

You certainly can remove the caches, and this is recommended every once in a while just to clean out any old programs linguring about.
 

karbo

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It's a new computer with a new XP Pro installation.

The time delay is a few seconds at startup, but I sure would like it to be constant all the time.
 
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The memory cache empties every time you turn off the machine, so there is nothing you can do but to allow it to re-initialize on a reboot. There are also background processes initializing at boot, so apps should open faster if you wait a few minutes after boot rather than starting right away.

In Vista, the ReadyBoost cache helps to some degree with this since it maintains its cache between boots. Using hibernate or sleep also maintains the contents of memory.
 

karbo

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Thanks for the info. By the way, is there something similare to ReadyBoost you could use in XP Pro?
 
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