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Help with subnetting assignment.

Discussion in 'Networking' started by Dlellis45, Nov 2, 2012.

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  1. Dlellis45

    Dlellis45 Thread Starter

    Joined:
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    Given an IP address range, select the correct subnet mask for the scenario. IP address: 200.4.82.0/24 You need to create 6 networks with a minimum of 28 hosts per network. What is the correct subnet mask and the 3rd subnet range?

    This is the answer I came up with. I just need to know if I'm on the right track...

    225.225.225.0 - 255.255.255.224
    200.4.82.64 - 200.4.82.95

    Thank you in advance,
    Denise
     
  2. Couriant

    Couriant Trusted Advisor

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    Messages:
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    First Name:
    James
    Welcome :)

    You are correct with the subnet mask. The netmask of 255.255.255.224 will give you 30 hosts minus 2 for network and broadcasting address. So your networks would be 200.4.82.0, 200.4.82.32, and 200.4.82.64.

    How did you come up with the subnet mask?
     
  3. Dlellis45

    Dlellis45 Thread Starter

    Joined:
    Nov 2, 2012
    Messages:
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    Thank you for your reply,

    I need 28 hosts per network, so I used /27. I hope I'm explaining myself correctly. This is all new to me.
    I came up with the IP address range because of the 3rd subnet range. I have as follows...

    1.) 200.4.82.0 - 200.4.82.31
    2.) 200.4.82.32 - 200.4.82.63
    3.) 200.4.82.64 - 200.4.82.95
    4.) 200.4.82.96 - 200.4.82.127
     
  4. Couriant

    Couriant Trusted Advisor

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    Messages:
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    First Name:
    James
    Your ranges are correct. :)

    The reason for my question is to make sure you know how to quickly figure out the CIDR (subnet mask). :)
     
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