Javascript Rollover.

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llckll

Thread Starter
Joined
Apr 8, 2004
Messages
70
I'm sorry about the previous post. let me be more specific.

Here is the javascript source code i am calling in my html page:

function initRollovers() {
if (!document.getElementById) return

var aPreLoad = new Array();
var sTempSrc;
var aImages = document.getElementsByTagName('img');

for (var i = 0; i < aImages.length; i++) {
if (aImages.className == 'imgover') {
var src = aImages.getAttribute('src');
var ftype = src.substring(src.lastIndexOf('.'), src.length);
var hsrc = src.replace(ftype, '_o'+ftype);

aImages.setAttribute('hsrc', hsrc);

aPreLoad = new Image();
aPreLoad.src = hsrc;

aImages.onmouseover = function() {
sTempSrc = this.getAttribute('src');
this.setAttribute('src', this.getAttribute('hsrc'));
}

aImages.onmouseout = function() {
if (!sTempSrc) sTempSrc = this.getAttribute('src').replace('_o'+ftype, ftype);
this.setAttribute('src', sTempSrc);
}
}
}
}

window.onload = initRollovers;

here is the html code i currently have up:

<html>
<head>
<title>Luxury Travel</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<script src="js/rollover.js" type="text/javascript"></script>
</head>
<body bgcolor="#FFFFFF" text="#000000">
<table width="740" cellspacing="0" cellpadding="0" border="0" align="center">
<tr>
<td><img src="images/logo.gif"></td>
</tr>
</table>
<table width="740" height="2" cellspacing="0" cellpadding="0" border="0" align="center">
<tr>
<td><img src="images/spacer.gif"></td>
</tr>
</table>
<table width="740" height="306" cellspacing="0" cellpadding="0" border="0" align="center">
<tr>
<td style="padding-left: 10px" bgcolor="000000"><img src="images/default_pic.gif" vspace="10"></td>
<td width="240" height="306" valign="top" align="center" bgcolor="000000" style="padding-right: 10px; padding-top: 10px">
<table width="240" cellspacing="0" cellpadding="0">
<tr>
<td align="center" bgcolor="434343"><img src="images/new_york.gif" vspace="10"></td>
</tr>
<tr>
<td align="center" bgcolor="434343"><img src="images/las_vegas.gif"></td>
</tr>
<tr>
<td bgcolor="434343" align="center"> <br>
<img src="images/image1.gif" vspace="4" hspace="4" class="imgover"><img src="images/image2.gif" vspace="4" hspace="4" class="imgover"><img src="images/image3.gif" vspace="4" hspace="4" class="imgover"></td>
</tr>
<tr>
<td bgcolor="434343" align="center"><img src="images/image4.gif" vspace="4" hspace="4" class="imgover"><img src="images/image5.gif" vspace="4" hspace="4" class="imgover"><img src="images/image6.gif" vspace="4" hspace="4" class="imgover"></td>
</tr>
<tr>
<td bgcolor="434343" height="21"></td>
</tr>
</table>
</td>
</tr>
</table>
<table width="740" height="2" cellspacing="0" cellpadding="0" border="0" align="center">
<tr>
<td><img src="images/spacer.gif"></td>
</tr>
</table>
<table width="740" cellspacing="0" cellpadding="0" border="0" align="center">
<tr>
<td><img src="images/footer.gif"></td>
</tr>
</table>
</body>
</html>


So basically, this is the situation. Images 1-6 are all black and white images. When I rollover those images, i have those same 6 images named the same, except i added '_o' to the image names which are in color.

so when i roll over any of the images, it works fine.

But this is where i face the problem.....

is there a way when i rollover the first image so that it changes to the color version named image1_o, but at the same time, in another table where default_pic is located, that pic, which is much bigger, also change?

so whichever image i'm on, the image in the other td will change at the same time the image1-6 is changing to image1-6_o?

Great, this is very confusing.. :confused:
 
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