Solved: Batch file issue - Program dettection

[raven6988]

Hello again,

I am having an issue with a .bat that I have written. All it does is tell me which version of a program is installed. But I am trying to remember how to write the FOR statement so that if the program is not installed it show a message and not the error stating the registry entry does not exist. It is a simple FOR statement but I am having issues writing the Else portion of it. All I get with the FOR statements I write with the else do not even work...

Please help.

Below is the Working For statement.

FOR /F "tokens=2* delims= " %%A IN ('REG Query "HKLM\SOFTWARE\Microsoft\Windows\CurrentVersion\Uninstall\SnagIt7" /v DisplayVersion') DO Set _Snaginf=%%B
echo . = SnagIt Version %_Snaginf% is installed.


Please help.

Thanks again.

 

[TheOutcaste]

Set _Snaginf=
FOR /F "tokens=2* delims= " %%A IN ('REG Query "HKLM\SOFTWARE\Microsoft\Windows\CurrentVersion\Uninstall\SnagIt7" /v DisplayVersion 2^>Nul') DO Set _Snaginf=%%B
If "%_Snaginf%"=="" (Echo.Snagit is not installed) Else echo.SnagIt Version %_Snaginf% is installed.

The 2^>Nul will keep the ERROR: The system was unable to find the specified registry key or value. message from being displayed.

 

[raven6988]

Thank you That really helps. How can I show an echoed message if a program is not found?

 

[TheOutcaste]

If the Snagit registry key is not found it displays Snagit is not installed. That's the Echo statement on the left side of the Else clause. Isn't that what you wanted?

 

[raven6988]

Yes I see it now. Thank you.