Solved: Java - for loop count range problem

[tjamnz]

Hello... I'm trying to count the total of all even numbers between the given range in Java.

I'm using a for loop, but am not getting the desired output.

// Code here

import java.util.Scanner;
public class SumEveryOtherNum {

public static void main (String[] args){

int num, sum = 0;
Scanner scan = new Scanner (System.in);
System.out.println ("Enter a number greater than 1: ");
num = scan.nextInt();

for (int count = 2; count <= num; count+=2){
sum+=count;
if (num < 1)
System.out.println ("Number entered not valid. Try again");
else
System.out.println("All even numbers added =" + (sum));
}

}

}

/*

If i enter the value 10 at the prompt, my output looks like this.
For some reason i figured "sum+=count" would add each number looped, and just output 30.
It prints this output instead:

Enter a number greater than 1:
10

output:
All even numbers added =2
All even numbers added =6
All even numbers added =12
All even numbers added =20
All even numbers added =30

Im trying to count the values, and for the result to only print the value of 30 such as:

All even numbers added = 30


Thanks for any ideas !

*/

 

[tjamnz]

import java.util.Scanner;
public class AnotherTest {


public static void main(String[] args) {

Scanner scan = new Scanner (System.in);

int sum = 0;
int upperLimit;
System.out.println("Enter an integer (Output will add numbers in between 2 and upperLimit): ");
upperLimit = scan.nextInt();

for (int current = 2; current <= upperLimit; current += 2)
sum += current;

System.out.println("Sum of even numbers between 2 and " + upperLimit + " inclusive is: " + sum);
// TODO Auto-generated method stub

}

}

// removed the if else statements from prev version